Question

At a certain fast-food restaurant, 56% of customers order a chicken sandwich, 43% of customers order french fries, and 30% of customers order both a chicken sandwich and french fries. What is the probability that a randomly selected customer will order a chicken sandwich or french fries (or both items)?

Answer 1

The probability that a randomly selected customer will order a chicken sandwich or french fries is 36%

How to determine the probability?

The given parameters are:

P(Chicken) = 56%

P(Sandwich) = 43%

P(Both) = 30%

The required probability is:

P = P(Chicken) + P(Sandwich) - P(Both)

This gives

P = 56% + 43% - 30%

Evaluate

P = 36%

Hence, the probability that a randomly selected customer will order a chicken sandwich or french fries is 36%

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