Question

What mass of silver nitrate, AgNO3, is needed to make 500.0 mL of 0.600 mol/L AgNO3(aq)?

Answer 1

50.97 g AgNO₃ is needed to make 500.0 mL of 0.600 mol/L AgNO3(aq)

What are moles?

A mole is defined as 6.02214076 × $10^{23}$of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Molar mass of AgNO₃ = (107.9 + 14.0 + 16.0×3) g/mol = 169.9 g/mol

Molarity = Moles of solute ÷ Volume of solution in litre

0.600 mol/L = Moles of solute ÷ 0.5 mL

Moles of solute =0.3 mol

Moles =$\frac{mass}{molar \;mass}$

0.3 mol =  $\frac{mass}{169.9 g/mol}$

Mass =50.97 g AgNO₃

Hence, 50.97 g AgNO₃ is needed to make 500.0 mL of 0.600 mol/L AgNO3(aq).

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