Question

find the values of m&n if x
2
−2
$f(x) = mx ^{4} + 2x ^{3} - 3x ^{2} + nx - 4$
​

Answer 1

The values of m and n from the given equation are 1/4 and -2

Polynomial functions

Given the polynomial function below

f(x) = mx^4+2x^3-3x^2+nx-4

If the zeros are 2 and -2, hence;

0 = 16m+16-12+2n-4
0 = 16m-16+12-2n-4

_______________
16m+2n = 0
16m - 2n = 8

Subtract

2n+2n = -8
4n = -8

n = -2

Substitute for "m'

16m + 2(-2) = 0
16m = 4

m = 1/4

Hence the values of m and n from the given equation are 1/4 and -2

Learn more on polynomials here; https://brainly.com/question/2833285

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