Question

The equation of a parabola is given. y=1/6x^2+2x+11 What are the coordinates of the vertex of the parabola? Enter your answer in the boxes

Answer 1

The coordinates of the vertex of the parabola are (-6,5).

How do we determine the coordinates of the vertex of the parabola?

The coordinates of a vertex of a parabolic equation are those x and y points for which the parabola crosses its axis of symmetry.

The vertex of an up-down facing parabola of the form y = ax² + bx + c is $\mathbf{x_v = -\dfrac{b}{2a}}$

$\mathbf{x_v = -\dfrac{2}{2(1/6)}}$

$\mathbf{x_v = -6}$

From the equation:

$\mathbf{y = \dfrac{1}{6}x^2+2x+11}$

$\mathbf{y_v = \dfrac{1}{6}(-6)^2+2(-6)+11}$

$\mathbf{y_v =5}$

Learn more about determining the coordinates of a vertex of a parabola here:

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