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A 0.250 L solution is made with 1.60 g of glucose, in water at 25.00∘C. What is the osmotic pressure of the solution?
Use −273.15∘C for absolute zero.
Use R=0.08206 L atmmol K for the ideal gas constant

Respuesta :

samueladesida43

The osmotic pressure of the 0.250 L solution made with 1.60 g of glucose, in water at 25.00°C is 0.869atm.

How to calculate osmotic pressure?

The osmotic pressure of the solution can be calculated using the following expression:

PV = nRT

where;

  • P = pressure
  • V = volume
  • n = no of moles
  • T = temperature
  • R = gas law constant

no of moles of glucose = 1.60g ÷ 180g/mol = 8.89 × 10-³mol

P × 0.250 = 0.00889 × 0.08206 × 298

0.25P = 0.217

P = 0.217/0.25

P = 0.869atm

Therefore, the osmotic pressure of the 0.250 L solution made with 1.60 g of glucose, in water at 25.00°C is 0.869atm.

Learn more about osmotic pressure at: https://brainly.com/question/10046758

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