Question

A sample of tin (Cp = 0.227 J/g•°C) is placed in a freezer. Its temperature decreases from 15.0°C to −10.0°C as it releases 543 J of energy. What is the mass of the sample? Round your answer to three significant figures.

Answer 1

We know, Q = m.c.Δt
m = Q / c.Δt

Here, Q = 543 J
c = 0.227 J/g C
Δt = 15-(-10) = 25 C

Substitute their values,
m = 543 / 0.227 * 25
m = 543 / 5.675
m = 95.68 g

In short, Your Answer would be 95.68 gram

Hope this helps!

Answer 2

The mass of the sample is 95.7 grams.

What is mass?

The average mass of an element's atoms, is expressed in atomic mass units.

Calculation:

Specific heat = Q = m.c.Δt

Given, Q = 543 J

c = 0.227 J/g CΔ

Δt = 15-(-10) = 25 C

where 15.0° C - 10.0 °C is the temperature difference

Now, from the equation

$\bold{m = \dfrac{543}{0.227} \times 25}$

Mass = 95.7 grams.

Thus, the mass of the sample is 95.7 grams.

Learn more about mass, here:

https://brainly.com/question/15959704