Question

What is the molar concentration of
a solution with a volume of 1.5 L
containing 660 g Ca3(PO4)2?

Answer 1

Answer:

1.42 M

Explanation:

First calculate the amount of moles.

that's done by dividing the mass with the molecular mass so 660g / 310.18 g/mol = 2.13 mol

Then you can calculate the molarity by dividing the moles with the volume so 2.13 mol / 1.5 l = 1.42 M

(without rounding: 1.418531175 M)