Given: a || b, transversal k
Prove <3 = <6
![Given a b transversal k Prove lt3 lt6 class=](https://us-static.z-dn.net/files/dc6/7c4c082f332a96faf130fc74b8ef5fc1.jpg)
By the property of corresponding angles ∠3 ≅ ∠5.
In geometry, a transversal is any line that intersects two straight lines at distinct points.
If two parallel lines are cut by a transversal, then each pair of corresponding angles are equals.
That is, ∠3 = ∠5 and ∠4 = ∠6.
Therefore the given angles ∠3 and ∠5 are equal.
Hence ∠3 ≅ ∠5 .
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