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3 moles of NaOH reacts with 1 mole of phosphoric acid.
The moles ratio of the reaction between NaOH and Phosphoric acid is given by the equation of the reaction below:
[tex]3\:NaOH + H_{3}PO_{4} \rightarrow Na_{3}PO_{4} + 3\:H_{2}O \\ [/tex]
Based on the equation of the reaction, 3 moles of NaOH reacts with 1 mole of phosphoric acid.
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