Respuesta :
Answer:
r= 1.09×10^-4
Explanation:
Given
V=speed=4.0×10^5 m/s
B= magnetic field= 0.040 T
©=angle= 35°
m= mass of electron= 9.11×10^-31
q= charge of electron= 1.60×10^-19
solution
qv×B= mv²/r
qvBsin©=mv²/r
qBsin©=mv/r
r=mv/qBsin©
r=9.11×10^-31× 4.0×10^5/1.064×10^-19×0.04T(sin35°)
r= 1.09×10^-4 m
a) r = 1.09 * [tex]10^{-4}[/tex] m
b) Distance travelled : 6.845 * [tex]10^{-4}[/tex] m
What is an electron ?
An electron is a stable subatomic particle with a charge of negative electricity, found in all atoms and acting as the primary carrier of electricity in solids.
given
charge of electron : 1.6 * [tex]10^{-19}[/tex] C
mass of electron = 9.11 * [tex]10^{-31}[/tex] kg
v = 4.0 x 10 m/s
B = 0.040 T
theta = 35 degrees
since ,
force in magnetic field on electron = centripetal force
a) q(v*B) = m [tex]v^{2}[/tex] / r
q v B sin(theta) = m [tex]v^{2}[/tex] / r
r =m v /q B sin(theta)
r = 9.11 * [tex]10^{-31}[/tex] * 4.0 x [tex]10^{5}[/tex]/ 1.6 * [tex]10^{-19}[/tex] sin (35)
r = 1.09 * [tex]10^{-4}[/tex] m
b) far forward will the electron have moved after completing one circle will be equal to circumference of the circle = 2πr
= 2 * 3.14 * 1.09 * [tex]10^{-4}[/tex] m = 6.845 * [tex]10^{-4}[/tex] m
learn more about electron
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