The (w/v)% concentration of vinegar contains 5g of acetic in 100mL of solution is approx 0.5 %
The concentration of a chemical substance expresses the amount of a substance present in a mixture.
There are many different ways to express concentration.(w/v)% is one of them.
Given ;
We need to convert the grams of acetic acid to moles ;
Formula of acetic acid is CH₃COOH
Thus,
Molar mass of acetic acid = 2(12.01) + 4(1.01) + 2(16)
= 24.02 + 4.04 + 32
= 60.06 grams per mol
Moles of acetic acid = 5.0/60.06
= 0.083 moles
(w/v)% = 0.083 x 60 / 1000 x 100
= 0.498 %
= 0.5 %
Hence, The (w/v)% concentration of vinegar contains 5g of acetic in 100mL of solution is approx 0.5 %
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