Answer:
[tex]\fbox {Trapezoid ABCD and Trapezoid EFGH are congruent.}[/tex]
Step-by-step explanation:
Finding corresponding side lengths :
Trapezium ABCD
- AB = √(-2)² + (-1)² = √5
- BC = √(-1)² + (2)² = √5
- CD = √(2)² + (2)² = 2√2
- DA = √(-1)² + (5)² = √26
Trapezium EFGH
- EF = √(2)² + (1)² = √5
- FG = √(1)² + (2)² = √5
- GH = √(-2)² + (2)² = 2√2
- HE = √(1)² + (5)² = √26
As the corresponding side lengths are equal, we can conclude that the trapezoids are congruent.
