[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
- [tex]\qquad \tt \rightarrow y = 5z [/tex]
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[tex] \large \tt Solution \: : [/tex]
[ let the point at which line segments SV and RT intersects be O ]
[tex]\qquad \tt \rightarrow \: \angle ROV + \angle ROS = 180° [/tex]
[ linear pair ]
[tex]\qquad \tt \rightarrow \: \angle ROV = 180 - \angle ROS[/tex]
[tex]\qquad \tt \rightarrow \: \angle ROV = 180 -2y[/tex]
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[tex]\qquad \tt \rightarrow \: \angle SVU = \angle ROV + \angle TRV[/tex]
[ Exterior angle = sum of opposite interior angles ]
[tex]\qquad \tt \rightarrow \: \angle SVU = 180 - 2y + y[/tex]
[tex]\qquad \tt \rightarrow \: \angle SVU = 180 - y [/tex]
( let it be equation 1 )
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[tex]\qquad \tt \rightarrow \: \angle SVU + \angle SUV + \angle VSU = 180°[/tex]
[ Sum of angles of Triangle ]
[tex]\qquad \tt \rightarrow \: \angle SVU + 4z + z = 180°[/tex]
[tex]\qquad \tt \rightarrow \: \angle SVU + 5z = 180°[/tex]
[tex]\qquad \tt \rightarrow \: \angle SVU = 180° - 5z[/tex]
( let it be equation 2 )
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By comparing both equations :
[tex]\qquad \tt \rightarrow \: \angle SVU = 180 - y = 180 - 5z[/tex]
[tex]\qquad \tt \rightarrow \: 180 - y = 180 - 5z[/tex]
( Add 180° on both sides )
[tex]\qquad \tt \rightarrow \: 180 - y + 180 = 180 - 5z + 180[/tex]
[tex]\qquad \tt \rightarrow \: - y = - 5z[/tex]
[tex]\qquad \tt \rightarrow \: y = 5z[/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
