Question

Given the quadratic function f(x)= 4x^2-4x+3, determine all possible solutions for f(x)=0

Answer 1

Answer:

f(x)=4x²-4x+3

f(x)=0

4x²-4x+3=0

-(-4)±√((-4)²-4.4.3)/2(4)

(4±√(16-48)/8

(4±√-32)/8

(4±i√32)/8

(4±i.4√2)/8

x=(4+4i√2)/8 or x=(4-4i√2)/8

x=4/8+4i√2/8 x=4/8-4i√2/8

x=1/2+i√2/2 or x= 1/2-i√2/2

•1/2±i√2/2