The amount of sulfuric acid needed to change the pH of a 512.2L of water to 5 is 0.50grams.
How to calculate number of moles?
To calculate the amount of sulfuric acid needed to change the pH of water to 5, the concentration of sulfuric acid must be calculated as follows:
Molarity of sulfuric acid = antilog -5 = 0.00001M
molarity = no of moles ÷ volume
no of moles = 0.00001 × 512.1 = 0.00512moles
mass of sulfuric acid = 0.00512moles × 98g/mol = 0.50g
Therefore, the amount of sulfuric acid needed to change the pH of a 512.2L of water to 5 is 0.50grams.
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