Question

The theoretical yield of silver was
determined at 241 g Ag through
calculation. Instead, the reaction
generated only 192 g Ag. What is the percent yield of the reaction?

2AgNO3 + Zn → 2Ag + Zn(NO3)2

[?] %

Answer 1

Answer:

79.7%

Explanation:

Percentage yield = (actual yield/theoretical yield)*100%

Therefore percentage yield for this experiment is: $\frac{192}{241} *100%$%

$= 0.79668*100$%

Percentage yield = 79.668%

Rounded to 3 significant figures is 79.7%

Hope this helped!