Respuesta :

Answer:

2-4i/5

Step-by-step explanation:

[tex]\frac{2i}{i-2} *\frac{i+2}{i+2}\\=\frac{2i(i+2)}{i^2-4}\\= \frac{2i(i+2)}{-1-4}\\ =\frac{2i(i+2)}{-5} \\ = \frac{-2 + 4i}{-5}\\ =( 2 - 4i )/ 5[/tex]

Answer:

[tex]\frac{2i}{i-2}=\frac{2-4i}{5}[/tex]

Step-by-step explanation:

  • [tex]\frac{2i}{i-2}[/tex] (Given)

  • [tex]=\frac{2i}{i-2}\times \frac{i+2}{i+2}[/tex] [Multiply numerator and denominator both by (i + 2)]

  • [tex]=\frac{2i(i+2)}{(i-2)(i+2)}[/tex]

  • [tex]=\frac{2i^2+4i)}{i^2-2^2}[/tex]

  • [tex]=\frac{2(-1)+4i)}{-1-4}[/tex]

  • [tex]=\frac{-2+4i)}{-5}[/tex]

  • [tex]=\frac{2-4i)}{5}[/tex]

  • [tex]\implies \frac{2i}{i-2}=\frac{2-4i}{5}[/tex]
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