Question

please help me
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Answer 1

Answer:

There are 16 notes of 20 paise's and 12 notes of 5 paise's.

Explanation:

The amount of notes for of 20 paise and 5 paise coins are not given.

So let there be x 20 paise's coins and y 5 paise's coins.

Equation buildup:

20x + 5y = 380 ___eq 1

20y + 5x = 380 - 60

20y + 5x= 320 ___ eq 2

Make x the subject for both:

1st

$\rightarrow \sf 20x + 5y = 380$

$\rightarrow \sf 20x = 380-5y$

$\rightarrow \sf x = 19-0.25y$

2nd

$\sf \rightarrow 20y + 5x = 320$

$\sf \rightarrow 5x = 320-20y$

$\sf \rightarrow x= 64-4y$

Solve them simultaneously:

$\sf \rightarrow 64-4y =19 - 0.25y$

$\sf \rightarrow -4y+0.25y =19 -64$

$\sf \rightarrow -3.75y =-45$

$\sf \rightarrow y =12$

Find x:

$\sf \rightarrow x = 64-4y$

$\sf \rightarrow x = 64-4(12)$

$\sf \rightarrow x = 16$