Question

What is the domain of the function
f(x) = $\sqrt{1/3 x + 2}$

Answer 1

The domain of the function is:

D: {x ∈ R | x ≥ -6}

How to get the domain of the function?

Here we have:

$f(x) = \sqrt{(1/3)*x + 2}$

Remember that the argument of a square root can be only numbers equal to or larger than zero, so the domain of that function is such that:

$(1/3)*x + 2 \geq 0$

Now we can solve that for x.

$(1/3)*x + 2 \geq 0\\(1/3)*x \geq -2\\\\x \geq -2*(3/1)\\\\x \geq -6$

So the domain of the function is:

D: {x ∈ R | x ≥ -6}

If you want to learn more about domains:

https://brainly.com/question/1770447

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Answer 2

Answer:

The domain of the function is:

D: {x ∈ R | x ≥ -6}