Question

A piecewise function is represented by the graph below.

On a coordinate plane, a piecewise function has 2 lines. The first line is made up of 2 lines. One line goes from (negative 5, 3) to (negative 1, negative 1) and then goes up to a closed circle at (1, 1). The second line has an open circle at (1, 2) and then continues up through (3, 4).
What is the domain for the piece of the function represented by f(x) = x + 1?

x < –1
–1 ≤ x ≤ 1
1 ≤ x < 2
x > 1

Answer 1

Because we have an open circle at (1, 2), and then the line continues up, we conclude that the domain is:

D: x > 1.

What is the domain for the piece of the function represented by f(x) = x + 1?

Here we know that:

"The second line has an open circle at (1, 2)"

This means that the value x = 1 is not on the domain of the second line, and we know that the line "then continues up through (3, 4)"

(notice that these are two points on the line y = x + 1).

So we conclude that x = 1 is the lower bound of the domain of that line (and we can't tell that there is an upper bound).

Then we can just write the domain as:

D: x > 1.

So the last option is the correct one.

If you want to learn more about domains:

https://brainly.com/question/1770447

#SPJ1