The polar coordinates of (-4, 150°) will be [tex]\sqrt[2]{5629}\\[/tex] and 5069.09939523°
What is the coordinate about?
The formula for this conversion will be:
r = [tex]\sqrt{x^2 + y^2}[/tex]
θ = [tex]tan ^-1 (\frac{y}{x} )[/tex]
[tex]r = \sqrt{(4^2) + (150^0)^2} \\\\θ = tan ^-1 (\frac{y}{x} )\\\\\\r = \sqrt[2]{5629} \\\\ = tan ^-1 (\frac{150}{4} )\\[/tex]
= [tex]\frac{75}{2}[/tex]
the inverse of: [tex]\frac{75}{2}[/tex] is θ = 5069.09939523°
Therefore:
[tex]r = \sqrt[2]{5629}\\[/tex]
θ = 5069.09939523°
So the polar coordinates of (-4, 150°) will be [tex]\sqrt[2]{5629}\\[/tex] and 5069.09939523°
Learn more about polar coordinates from
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