Please help me with my math

[tex] \sf{\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Let's solve for z and x ~
[tex]\qquad \sf \dashrightarrow \: 82 + z = 180[/tex]
[ they form co-interior angle pair ]
[tex]\qquad \sf \dashrightarrow \: z = 180 - 82[/tex]
[tex]\qquad \sf \dashrightarrow \: z = 98 \degree[/tex]
and
[tex]\qquad \sf \dashrightarrow \: z = (5x - 82)[/tex]
[ by Alternate interior angle pair ]
[tex]\qquad \sf \dashrightarrow \: 98 = 5x - 82[/tex]
[tex]\qquad \sf \dashrightarrow \: 5x = 98 + 82[/tex]
[tex]\qquad \sf \dashrightarrow \: 5x = 180[/tex]
[tex]\qquad \sf \dashrightarrow \: x = 180 \div 5[/tex]
[tex]\qquad \sf \dashrightarrow \: x = 36 \degree[/tex]
Answer:
z = 98
x= 36
Step-by-step explanation:
z + 82 = 180 -> due to same side interior angles adding up to 180
z = 180 - 82
z = 98
z = 5x - 82 due to opposite interior angles being equal
98 = 5x - 82
98+82 = 5x - 82+82
180 = 5x
180/5 = 5x/5
36 = x
To check:
z = 5x - 82
(98) = 5(36) - 82
98 = 180 - 82