See below for the verification of ∠ACD = ∠ABC + ∠BAC
How to verify the angles?
The following proof works for both triangles.
The sum of angles in a triangle is 180 degrees.
So, we have:
∠ABC + ∠BAC + ∠ACB = 180
Make ∠ACB the subject
∠ACB = 180 - ∠ABC - ∠BAC
The sum of angles on a straight line is 180 degrees.
So, we have:
∠ACD + ∠ACB = 180
Make ∠ACB the subject
∠ACB = 180 - ∠ACD
Substitute ∠ACB = 180 - ∠ACD in ∠ACB = 180 - ∠ABC - ∠BAC
180 - ∠ACD = 180 - ∠ABC - ∠BAC
Subtract 180 from both sides
- ∠ACD = - ∠ABC - ∠BAC
Multiply both sides by -1
∠ACD = ∠ABC + ∠BAC
Hence, ∠ACD = ∠ABC + ∠BAC has been verified
Read more about proofs at:
https://brainly.com/question/24839702
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