Question

50 POINTS+brainliest but reposting again because my points were used last time: How do you graph a quadratic equation in vertex form when the equation is a perfect square? Use x² -4x+4 as an example
you will be reported if your answer is absurd

Answer 1

Answer:

If it is a perfect square, k=0 in the form y=a(x-h)^2+k.

Step-by-step explanation:

x^2-4x+4=(x-2)^2, meaning that the vertex is at the point (2,0).

Hope this helped :)

Answer 2

Answer:
If it is a perfect square, k=0 in the form
y=a(x-h) ^2+k.
Step-by-step explanation:
x^2-4x+4=(×-2) ^2, meaning that the vertex
is at the point (2,0).