BaCl2(aq)+Na2SO4(aq)⟶BaSO4(s)+2NaCl(aq)
Using the balanced chemical equation, determine how many moles of NaCl will be produced, if 0.731 mol of BaCl2 is allowed to react with an excess of Na2SO4.

Respuesta :

Answer:

1.46 moles NaCl

Explanation:

To find the moles of NaCl, you need to multiply the given value (0.731 moles BaCl₂) by the mole-to-mole ratio of the two relevant molecules. This ratio is made up of the coefficients in the balanced reaction. The numerator should contain moles NaCl to allow for the cancellation of moles BaCl₂. The final answer should have 3 sig figs to reflect the given value.

1 BaCl₂(aq) + Na₂SO₄(aq) ---> BaSO₄(s) + 2 NaCl(aq)

0.731 mole BaCl₂           2 moles NaCl
---------------------------  x  -------------------------  = 1.46 moles NaCl
                                         1 mole BaCl₂

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