Question

Need help finding the quadratic function...15 pts for your help

Answer 1

The function is $y = (x +2)^2 + 5.$

we use the vertex form of the quadratic equation

We have given a graph,

What is the vertex form of the quadratic equation?

y = a(x - h)^2 + k.

Therefore the vertex of the given graph is

See the vertex at (-2, 5)

Since the general way to write the vertex is (h, k), we compare (h, k) to (-2, 5).

$y = a(x - (-2))^2 + 5.\\y=a(x+2)^2+5......(1)$

Now we have given that (-4,1) use this value in the above equation so we get,

$(1)=a(-4+2)^2+5$

$1=a(-2)^2+5$

$1=4a+5$

$1-5=4a$

$-4=4a$

$a=-4/4$

$a=-1$

Using the value of an in equation (1) we get,

Therefore the function is $y = (x +2)^2 + 5.$

To learn more about the function visit:

https://brainly.com/question/4025726

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