Question

PLEASE ANSWER ASAP!!!!!11
The nth term of a sequence is represented by 2n^3+25n^2+32n−15/ 6n^4+2n^3−11n^2−2n+17.

What is the limit of the the nth term as x becomes increasingly large?

A. 0
B. 1/3
C. 3
D. The limit does not exist

Answer 1

The limit of the nth term of a sequence does not exist option (D) is correct.

What is the limit?

A limit is a value at which a function approaches the output for the given values in mathematics. Limits are used to determine integrals, derivatives, and continuity in calculus and mathematics.

We have an expression:

$= \rm \dfrac{2n^5+25n^2+32n-15}{6n^4+2n^3-11n^2-2n+17}$

Applying limit:

$= \lim_{n \to \infty} \rm \dfrac{2n^5+25n^2+32n-15}{6n^4+2n^3-11n^2-2n+17}$

$=\lim _{n\to \infty \:} n \left(\dfrac{2+\dfrac{25}{n^3}+\dfrac{32}{n^4}-\dfrac{15}{n^5}}{6+\dfrac{2}{n}-\dfrac{11}{n^2}-\dfrac{2}{n^3}+\dfrac{17}{n^4}}\right)$

= ∞ = The limit does not exist

Thus, the limit of the nth term of a sequence does not exist option (D) is correct.

Learn more about the limit here:

brainly.com/question/8533149

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