Question

In a spelling bee $50\%$ of the students were eliminated after the first round. Only $\frac{1}{3}$ of the remaining students were still in the contest after the second round. If 24 students were still in the contest after the second round, how many students began the contest

Answer 1

There were 144 students when the contest began

What is Equation ?

Equation is formed when an algebraic expression is equated by a constant or another algebraic expression.

On the basis of given data :

Let the total number of students are x

50% of the students are eliminated after the first round

the remaining students are 0.5x

After the second round = (1/3) * 0.5 x were remaining

and

(1/3) * 0.5 x = 24

then solving this equation will give the total number of students

0.5x = 24 * 3

x = 24*3 /0.5 = 144

Therefore there were 144 students when the contest began

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