Question

can someone please help mee

Answer 1

Answer:

$f(z) = z^2-3z+2$

$f(x+1) = x^2-x$

$f(\sqrt{2}+1) = 2-\sqrt{2}$

Step-by-step explanation:

$f(x+1) = x^2+2x+1-3x-3+2$

$f(\sqrt{2}+1) = 2+2\sqrt{2}+1-3\sqrt{2}-3+2$