Question

If L (-5,4),M(2,2), N(0,-3), S(-7,-1), what is the length of diagonal LN

Answer 1

The length of the diagonal LN would be 8.60 units.

To find the distance between the two coordinates, We use distance formula ;

$d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}$
Lets put the values of L and N,
d= $\sqrt{(0 - -5)^2 + (-3-4)^2}$

d =$\sqrt{25+49}$

d= $\sqrt{74}$

d= 8.60 units

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