Question

what is the distance between points D and H? Round to the nearest tenth of a unit. A.)3.7 units B.) 5.2 units C.)7.3 units D.)9.4 units PLEASE HELP

Answer 1

Use the distance formula.

$\sf\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

(1, 3), (9, 8)
x1 y1  x2 y2

$\sf\sqrt{(9 - 1)^2 + (8 - 3)^2}$

$\sf\sqrt{(8)^2 + (5)^2}$

$\sf\sqrt{64 + 25}$

$\sf\sqrt{89}$

$\sf\approx 9.4 $

Answer 2

Answer

Find out the  distance between points D and H .

To prove

Now apply the distance formula

$Distance\ formula = \sqrt{(x_{2} -x_{1})^{2} +(y_{2} -y_{1})^{2}}$

The points be  D (1,3)and H (9,8)

Put in the formula

$DH = \sqrt{(9 -1)^{2} +(8 -3)^{2}}$

$DH = \sqrt{(8)^{2} +(5)^{2}}$

$DH = \sqrt{64+25}$

$DH = \sqrt{89}$

As

$\sqrt{89} = 9.4(approx)$

DH = 9.4 units (approx)

Option (D) is correct .