Question

x + 4 = x2? Assume x greater-than 0

Answer 1

Answer:

The  value comes out to be  

$x=\frac{1}{2}+\frac{\sqrt{17}}{2}$

Step-by-step explanation:

The quadratic equation is an equation containing a single variable of degree $2$. Its general form is $ax^{2} +bx + c=0$.

The discriminant is the part of the quadratic formula underneath the square root symbol: b²- 4ac. The discriminant tells us whether there are two solutions, one solution, or no solutions.

The equation we are given is :$x+4=x^{2} \\x^{2} -x-4=0$

We know the formula as :

$x=[-b$±$\sqrt{b^{2}-4ac}]$ ×$\frac{1}{2a}$

$x=[-(-1)$±$\sqrt{(-1)^{2} -4(1)(-4)}]$×$\frac{1}{2(1)}$

$x=\frac{1}{2}$ ±$\frac{\sqrt{17} }{2} }$

Since $x$≥$0$

Other negative option is neglected

$x=\frac{1}{2}+\frac{\sqrt{17}}{2}$

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