The beta decay equation for the transmutation of a radioactive isotope of Rutherfordium has been explained above will be,[tex]\rm Re_{104}^{287} + \beta_0^{-1} \rightarrow Re_{104}^{286}[/tex]
The reduction in the number of radionuclides per unit time is the rate of decay.
The beta decay equation for the transmutation of a radioactive isotope of Rutherfordium has 104 protons and 183 neutrons.
Atomic weight = 104+183 = 287
Atomic number = 104
The beta decay equation is;
[tex]\rm Re_{104}^{287} + \beta_0^{-1} \rightarrow Re_{104}^{286}[/tex]
Hence the beta decay equation for the transmutation of a radioactive isotope of Rutherfordium has been explained above.
To learn more about the rate of decay refer to the link;
https://brainly.com/question/14486631
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