Answer:
The factors of the given equation are:
(11x−8)(11x+2)
Step-by-step explanation:
Since both terms are perfect squares,
Factorize using the difference of squares formula,
[tex]a^{2} -b^{2}[/tex][tex]=(a+b)(a-b)[/tex]
where a=11x−3 and b=5.
=> (11x-3+5)(11x-3-5)
=> (11x+2)(11x−8)
=>[tex](11x-3)^{2}-25[/tex]
Use the binomial theorem [tex](a-b)^{2}=a^{2} +b^{2} -2ab[/tex] to expand[tex](11x-3)^{2}-25[/tex]
=> [tex](11x^{2})+(3)^{2}- 2(11x)(3)-25[/tex]
=>[tex]121x^{2} + 9 - 66x -25[/tex]
=> [tex]121x^{2} -16+ 66x[/tex]
By the splitting method,
=> (11x−8)(11x+2)
The factors of the equation are (11x−8)(11x+2).
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