Question

Becky races Tom down the street .Becky , initially at a stop,takes 5.5 s to reach 30 m/s . What accelerated?

Answer 1

Becky's acceleration is 5.45 $ms^2$.

Acceleration = $\frac{v-u}{t}$

where v= final velocity , u= initial velocity , t= time taken

according to the question :

initial veocity = 0 (it is at stop initially)

final velocity = 30m/s

time taken = 5.5 s

according to the formula acceleration = $\frac{30-0}{5.5}$=$5.45$

Hence Becky's acceleration is 5.45 $ms^2$.

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