Which function is positive for the entire interval [–3, –2]? On a coordinate plane, a curved line with a minimum value of (0, negative 3) crosses the x-axis at (negative 3, 0) and (3, 0), and crosses the y-axis at (0, negative 3). On a coordinate plane, a curved line with a minimum value of (2, negative 3) crosses the x-axis at (negative 1, 0) and (5, 0), and crosses the y-axis at (0, negative 1.5). On a coordinate plane, a curved line with a minimum value of (2, 4) and a maximum value of (0.5, 6), crosses the x-axis at (negative 1.5, 0) and crosses the y-axis at (0, 5). On a coordinate plane, a curved line with a minimum value of (negative 1.75, negative 3.9) and a maximum value of (0, 2), crosses the x-axis at (negative 2.2, 0), (negative 0.75, 0), and (0.75, 0), and crosses the y-axis at (0, 2). Mark this and return

Four alternative graphs representing various functions are supplied to us; our task is to identify the function graph that is positive over the whole range [-3, -2]. A closed interval exists. Therefore, it includes both -3 and -2.

The graph of the Y value must be in a positive area during this interval. Therefore, we must choose a function that is positive over the whole range [-3, -2].

Looking at the graph, we can see that the graph B has positive y-values in the range [-3, -2].

Hence The function is shown to be positive throughout the whole range [-3, -2] in graph (B).

Learn more about Graph here:

https://brainly.com/question/4025726

#SPJ10