Question

Problem
Suppose that J is between H and K. If HJ=2x+4, JK=3x+3, and KH=22, find the lengths of HJ and JK. Remember to always draw an image first and to pay attention to what the question is asking for!



Solution
Find the Segment Addition Postulate
Use the Segment Addition Postulate and then substitute what we know. Do not use any spaces in your answers.

HJ+JK= Answer

( Answer
)+( Answer
)= Answer



Find x
Once we combine our like terms we get:

Answer
x+ Answer
= Answer

x= Answer



Find HJ and JK
Our questions asked us for the lengths of HJ and JK so we must plug in the value of x to solve for those values. We were given HJ=2x+4 and JK=3x+3.

HJ=2x+4

HJ=2( Answer
)+4

HJ= Answer

And

JK=3x+3

JK=3( Answer
)+3

JK= Answer
3x-4



Check Work
View checked work

Answer 1

Answer:

The lengths of HJ and JK are 50 and 72 respectively.

Given:

J is between H and K.

HJ=2x+4

JK=3x+3

HK=22

Step-by-step explanation:

The total length is given as:

HJ+JK=HK

⇒ (2x+4)+(3x+3)=22

⇒ 5x+7=22

⇒ 5x=22-7

⇒ 5x=15

⇒ x=3

Thus, the length of HJ is (2x+4)=(2*3+4)=10

And the length of JK is (3x+3)=(3*3+3)=12

See more detailed solution at

https://brainly.com/question/27943430

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Answer 2

The lengths of HJ and JK are 50 and 72 respectively.

Given: J is between H and K. the length of HJ=2x+4, JK=3x+3, and HK=22.

The line HJ and JK are  collinear then the total length is given as: HJ+JK=HK

substitute values

⇒ (2x+4)+(3x+3)=22

⇒ 5x+7=22

⇒ 5x=22-7

⇒ 5x=15

⇒ x=3

Thus, the length of HJ is (2x+4)=(2*3+4)=10

And the length of JK is (3x+3)=(3*3+3)=12

Learn more about collinear lines here: brainly.com/question/27943430

#SPJ10