Answer:
log_{b} (5b) = 2.609
Given that:
log_{b} (3) = 1.099
log_{b} (5) = 1.609
Evaluating with that:
[tex]\sf log_b (5b) = log_b\left(5\right)+log_b\left(b\right)[/tex]
[tex]= \sf 1.609 + 1[/tex]
[tex]= \sf 2.609[/tex]
Rule Used:
[tex]\rm \log _a\left(xy\right)=\log _a\left(x\right)+\log _a\left(y\right)[/tex]
