Question

please help me with this

Answer 1

The range of possible heights is given by the inequality:

d ≥ 300.125 m

How to find the possible heights of the building?

We know that the time that it takes for an object to fall from a distance d is:

$t = \frac{\sqrt{2d} }{4.9}$

In this case, we know that t ≥ 5s.

Then we can solve for the minimum distance, which is given when t = 5s.

$5 = \frac{\sqrt{2d} }{4.9}\\\\(5*4.9)^2/2 = d = 300.125$

So the minimum height of the building is 300.125 meters, then the range of possible heights is:

d ≥ 300.125 m

If you want to learn more about inequalities:

https://brainly.com/question/18881247

#SPJ1