Step-by-step explanation:
Hi there!
According to the question;
The gradient of line is 1/2 and passes through the point (4,-2).
Since, It has one point and gradient we use one point formula to find the equation of the line.
Note:
One point formula: (y-y1) = m (x-x1)
(4,-2) = (x1,y1)
So, using this formula we get;
(y+2) = 1/2(x-4)
Multiply both sides by 2.
2(y+2) = (1/2)*2(x-4)
2y+4 = x-4
Take 2y+4 in right side
0 = x-4 - (2y+4)
Therefore, x-2y-8 = 0 is the required equation.
Hope it helps!
