Question

A coin is located 35.0 mm from the center of a turntable which accelerates from rest to a speed of 7.95 rad/s in 0.270 s. What is the minimum coefficient of friction to avoid slippage of the coin

Answer 1

The minimum coefficient of friction to avoid slippage of the coin is 0.23.

Minimum coefficient of friction

The minimum coefficient of friction can determined from the maximum speed of the coin.

ma = μmg

mv²/r = μmg

v²/r = μg

v² = μgr

μ = v²/(gr)

μ = (ωr)²/(gr)

μ = ω²r/g

μ = (7.95² x 0.035)/(9.8)

μ = 0.23

Learn more about coefficient of friction here: https://brainly.com/question/20241845

#SPJ11