Respuesta :
Answer:
[tex]4a^2b^2c^3\left(\sqrt[3]{b}\right)[/tex]
Step-by-step explanation:
**Please note that the expression quoted in the question is likely incorrect (see attachment)**
Assuming the expression is:
[tex]\sqrt[3]{64a^6b^7c^9}[/tex]
[tex]\textsf{Apply radical rule} \quad \sqrt{ab}=\sqrt{a}{ \cdot \sqrt{b}[/tex]
[tex]\implies \sqrt[3]{64} \cdot \sqrt[3]{a^6}\cdot \sqrt[3]{b^7}\cdot \sqrt[3]{c^9}[/tex]
Rewrite 64 as 4³:
[tex]\implies \sqrt[3]{4^3} \cdot \sqrt[3]{a^6}\cdot \sqrt[3]{b^7}\cdot \sqrt[3]{c^9}[/tex]
[tex]\textsf{Apply exponent rule} \quad a^{b+c}=a^b \cdot a^c \quad \sf to\:\:b^7[/tex]
[tex]\implies b^7=b^{6+1}=b^6b^1=b^6b[/tex]
Therefore:
[tex]\implies \sqrt[3]{4^3} \cdot \sqrt[3]{a^6}\cdot \sqrt[3]{b^{6}b}\cdot \sqrt[3]{c^9}[/tex]
[tex]\implies \sqrt[3]{4^3} \cdot \sqrt[3]{a^6}\cdot \sqrt[3]{b^{6}}\cdot \sqrt[3]{b}\cdot \sqrt[3]{c^9}[/tex]
[tex]\textsf{Apply exponent rule} \quad \sqrt[n]{a^m}=a^{\frac{m}{n}}[/tex]
[tex]\implies 4^{\frac{3}{3}} \cdot a^{\frac{6}{3}} \cdot b^{\frac{6}{3}} \cdot \sqrt[3]{b} \cdot c^{\frac{9}{3}}[/tex]
Simplify:
[tex]\implies 4^1 \cdot a^2 \cdot b^2 \cdot \sqrt[3]{b} \cdot c^3[/tex]
[tex]\implies 4a^2b^2c^3\left(\sqrt[3]{b}\right)[/tex]

- ³√64ab²c³
- √4³ab²c³
- 4c√a^{2/3}b^{2/3}
The expression is seemed to have none of the above solutions