Question

Find three consecutive integers such that the
sum of the first and the third is 32.

Answer 1

The three consecutive integers are 15 16 and 17.

Step 1:

Let  X be the first integer. Since they are consecutive, it means that the second number will be X + 1 and the third number will be X + 2 and sum of the first and the third should add up to 32. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) be the three consecutive integers.

Step 2:

The sum of the first and the third should add up to 32.

X + ( X + 2 )= 32

2X + 2= 32

2X = 32 - 2

2X = 30

X = 30/2

X=15

Hence the first number is 15, the second number is 15 + 1, and the third number is 15 + 2.

Therefore, three consecutive integers in which the sum of the first and the third is 32 are 15 16, and 17.

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Answer 2

Answer: 15, 16 and 17

Step-by-Step Explanation:

Let the first integer be ‘a’

Therefore, since they are consecutive, the next 2 integers will be (a + 1) and (a + 2). We know, sum of first integer (a) and third integer (a + 2) is 32.

Therefore,
a + a + 2 = 32
2a + 2 = 32
2a = 32 - 2
2a = 30
a = 30/2
=> a = 15

Finding each Integer :-

1st No. = 15
2nd No. = 15 + 1 = 16
3rd No. = 15 + 2 = 17

Hence, the 3 integers are 15, 16 and 17.