Question

-3(2x-5)<5(2-x)
Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options.

x < 5
–6x – 5 < 10 – x
–6x + 15 < 10 – 5x
A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.
A number line from negative 3 to 3 in increments of 1. An open circle is at negative 5 and a bold line starts at negative 5 and is pointing to the left.

Answer 1

The correct option is an open circle at 5 and a bold line starts at 5 and is pointing to the right.

The given inequality is -3(2x-5)<5(2-x).

What is inequality?

Inequality is a declaration of an order relationship between two numbers or algebraic expressions, such as greater than, greater than or equal to, less than, or less than or equal to.

At first simplify each side

LHS of inequality -3(2x - 5) = -3(2x) + -3(-5) [∵(-)(-) = (+)]

⇒ -3(2x - 5) = - 6x + 15

Now, RHS of the inequality 5(2 - x) = 5(2) + 5(-x) [∵(+)(-) = (-)]

⇒ 5(2 - x) = 10 - 5x

Now, - 6x + 15 < 10 - 5x

Subtract 15 from both sides

That is, - 6x < -5 - 5x

Add 5x to both sides

That is, - x < - 5

Remember the coefficient of x is negative, and then when you divide both sides by it you must reverse the sign of inequality.

Now, the coefficient of x is -1

So, divide both sides by -1

Then, x > 5.

Hence, the correct option is an open circle at 5 and a bold line starts at 5 and is pointing to the right.

To learn more about inequality visit:

https://brainly.com/question/20383699.

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