At 11.3°C the rod will just come into contact
Coefficient of linear expansion of aluminium [tex]\alpha_{Al}[/tex] = [tex]23*10^-^6[/tex] °[tex]C[/tex]
Coefficient of linear expansion of Brass [tex]\alpha_{B} =19*10^-^6[/tex] °[tex]C[/tex]
[tex]\alpha = \Delta{L}/Lo(T2-T1)[/tex]
For aluminium
[tex]\alpha_{Al} = \Delta{L}/Lo(T-0)[/tex]
[tex]\Delta{L_{1}} = (23*10^-^6*50*T)[/tex]
For Brass
[tex]\alphaB = \Delta{L_{2}/Lo(T-0)[/tex]
[tex]\Delta{L_{1} +\Delta{L_{2} =0.024cm(23*10^-^6*50*T)+(19*10-6*50*T) =0.024[/tex]
T =11.43 °C
Learn more about linear expansion here:
https://brainly.com/question/24215446
#SPJ10