Question

Find the area of a cylinder of radius 4 cm and height 5 cm

Answer 1

Answer:

226.19cm^2

Step-by-step explanation:

Total surface area of cylinder = 2πr(r + h).

Answer 2

✠ Given:-

• Radius of the Cylinder = 4 cm
• Height of the Cylinder = 5 cm

✠ To Find:-

• Area of the Sphere = ??

✠ Solution:-

⚘ Here , we Have Given That Radius of the Sphere is 4 cm and Height of the Cylinder is 5 cm. we have to find the Area of the Cylinder , We know that formula used to find the area; Area of Cylinder = 2πr²+2πrh.....

☼ Calculating the Area of the Cylinder;

$\\ \sf \implies \: Area_{ \red{ \{Cylinder \}}} \: = \: \: 2 \: \pi \: r {}^{2} + 2 \: \pi \: r \: h$

$\\ \sf \implies \: Area_{ \red{ \{Cylinder \}}} \: = \bigg( \: 2 \: \times \: \frac{22}{7} \: \times \: 4{}^{2} \bigg)+ \bigg(2 \: \times \: \frac{22}{7} \: \times \: 4 \: \times \: 5 \bigg)$

$\\ \sf \implies \: Area_{ \red{ \{Cylinder \}}} \: = \bigg( \: 2 \: \times \: \frac{22}{7} \: \times \: 4 \: \times \: 4 \bigg)+ \bigg(2 \: \times \: \frac{22}{7} \: \times \: 4 \: \times \: 5 \bigg)$

$\\ \sf \implies \: Area_{ \red{ \{Cylinder \}}} \: = \bigg( \: 2 \: \times \: \frac{22}{7} \: \times \: 16 \bigg)+ \bigg(2 \: \times \: \frac{22}{7} \: \times \: 20\bigg)$

$\\ \sf \implies \: Area_{ \red{ \{Cylinder \}}} \: = \bigg( \: \frac{2 \times 22 \times 16}{7}\bigg)+ \bigg( \: \frac{2 \times 22 \times 20}{7} \bigg)$

$\\ \sf \implies \: Area_{ \red{ \{Cylinder \}}} \: = \bigg( \: \frac{704}{7}\bigg)+ \bigg( \: \frac{880}{7} \bigg)$

$\\ \sf \implies \: Area_{ \red{ \{Cylinder \}}} \: = \bigg( \: \frac{704}{7}\bigg)+ \bigg( \: \frac{880}{7} \bigg)$

$\\ \sf \implies \: Area_{ \red{ \{Cylinder \}}} \: = 100.57 \: \: +125.7 \: \:$

$\\ \sf \implies \: Area_{ \red{ \{Cylinder \}}} \: = 226 \: cm\:$

$\\ \\ ✠ \: \: { \underline{\bf { \color{blue}{ \: \: Additional \: \: Information :- \: \: }}}}$

⇥ Perimeter of rectangle = 2(length× breadth)

⇥ Diagonal of rectangle = √(length ²+breadth ²)

⇥ Area of square = side²

⇥ Perimeter of square = 4× side

⇥ Volume of cylinder = πr²h

⇥ T.S.A of cylinder = 2πrh + 2πr²

⇥ Volume of cone = ⅓ πr²h

⇥ C.S.A of cone = πrl

⇥ T.S.A of cone = πrl + πr²

⇥ Volume of cuboid = l × b × h

⇥ C.S.A of cuboid = 2(l + b)h

⇥ T.S.A of cuboid = 2(lb + bh + lh)

⇥ C.S.A of cube = 4a²

⇥ T.S.A of cube = 6a²

⇥ Volume of cube = a³

⇥ Volume of sphere = 4/3πr³

⇥ Surface area of sphere = 4πr²

⇥ Volume of hemisphere = ⅔ πr³

⇥ C.S.A of hemisphere = 2πr²

⇥ T.S.A of hemisphere = 3πr²