Answer: The answer is x < 5/2 and x > -5.
Step-by-step explanation:
First you need to separate the inequality and keep x on one side to maintain consistency. For instance the problem-
[tex]\frac{5-2x}{3} > 0\\\frac{5-2x}{3} < 5\\[/tex]
Now solve as normal.
*Note: When dividing a side or multiplying a side by a negative number, the sign of the inequality switches (this will be shown when I do the equation if it doesn't make since how I word it).
[tex]5-2x > 0*3\\5-2x < 5*3[/tex]
[tex]-2x > 0-5\\-2x < 15-5[/tex]
[tex]x < \frac{-5}{-2} =x < \frac{5}{2} \\x > \frac{10}{-2} =x > -5[/tex]
So, x < 5/2 and x > -5.
If anything is confusing about the procedure just leave a comment, and I'll try to explain further.
