Answer: 0.6906 g/cm^3
Explanation:
[tex]$We know that density $=\frac{\text { mass }}{\text { volume }}$\\\\Volume of the cube, $V=l^{3}=(1.500 \mathrm{~cm})=3.375 \mathrm{~cm}^{3}$\\\\Density of the cube $=\frac{2.331 \mathrm{~g}}{3.375 \mathrm{~cm}^{3}}=0.6906 \mathrm{~g} / \mathrm{cm}^{3}$\\\\ \therefore{\text{Density of the cube,} \ $\rho_{\text {cube }}{=0.6906 \mathrm{~g} / \mathrm{cm}^{3}$[/tex]