CPM homework 8.1.2 problem 8-19
![CPM homework 812 problem 819 class=](https://us-static.z-dn.net/files/d3c/3e431e3ad9bc8cfaabe191f8b868b7b2.jpeg)
The area of the figure is 45 sq.mi and the perimeter is 23.5354 mi.
Area is the space occupied by a two dimensional object,
The area and perimeter of the given shape can be determined by dividing it into basic shapes.
The area and the perimeter of the shape given = Area of the rectangle +Area of upper triangle - Area of two small triangles at the bottom
Area of rectangle = 5 mi * 9 mi = 45 sq.mi
Area of upper Triangle = (1/2) *9*3 = 27/2 sq.mi
Area of small Triangle = (1/2) * 3*6 = 9 sq.mi
Area of other small Triangle = (1/2)*3*3 = 9/2 sq.mi
Area of the figure = 45 +13.5 -9-4.5
Area of the figure = 45 sq.mi
Similarly for Perimeter = Perimeter of the rectangle +Perimeter of upper triangle -Perimeter of two small triangles at the bottom
Perimeter = 28 -(3+6+6.708) -(3+3+4.2426) +(3+9+9.486
Perimeter = 23.5354 mi
Therefore , The area of the figure is 45 sq.mi and the perimeter is 23.5354 mi.
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