The solution of the equation would be options A. -4 & 2.
A quadratic equation is the second-order degree algebraic expression in a variable.
The standard form of this expression is ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.
The given expression is
[tex]1/4x^2 = -1/2x+2\\\\1/4x^2 +1/2x-2= 0\\\\[/tex]
[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\x = \dfrac{-1/2 \pm \sqrt{1/4 - 4(1/4)(-2)}}{2(1/4)}\\\\\\x = \dfrac{-1/2 \pm \sqrt{1/4 +(2)}}{1/2}\\\\\\x = \dfrac{-1/2 \pm \sqrt{(9/4)}}{1/2}\\\\\\x = \dfrac{-1/2 \pm3/2}{1/2}\\\\x = -4, 2[/tex]
Therefore, the solution of the equation would be option A. -4 & 2.
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